abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

If the sun ran out of energy what would happen to the energy resources on earth
what is a similar quote for Romeo and Juliet "my bounty is as boundless as the sea . My love as deep , the more i give to thee , the more i have , for both are
What's the answer to this problem?
If the probability of giving birth to a boy is 0.52, what is the approximate probability of giving birth to 4 consecutive boys?
Find the sum of 2/9+1/9?
How many union ships did the Virginia sink?
if the score is 90% and the total is 70 what is the number correct ?
Bethany's dog eats 450 grams of food per day. How many kilograms does the dog eat in a week
What is the Difference between Research and Investigation???
Select the simplified expression for 8(x - 4) - 4(x - 3) + 7x. 11x + 4411x - 711x - 4411x - 20