Respuesta :

Alfpfeu

Answer:

answer B is correct

Step-by-step explanation:

Hello,

this is not allowed to divide by 0 so we need to find the zeros of

[tex]x^2+2x-15=0[/tex]

[tex]<=> x^2-3x+5x-15=0\\<=> x(x-3)+5(x-3)=0\\<=> (x+5)(x-3)=0\\<==> x=-5 \ \ or \ \ x=3[/tex]

we need x different from -5 and from 3

answer B is correct

hope this helps

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